By Omar Al-khayam

ISBN-10: 1435634772

ISBN-13: 9781435634770

ISBN-10: 1859641806

ISBN-13: 9781859641804

Omar Al-Khayyam's well-known ebook on algebra and equations is taken into account to be maybe his most vital contribution to arithmetic - the cream of his paintings. students of arithmetic regard the publication as a vital merchandise in either their own libraries and institutional collections. This ebook offers with the answer of quadratic and cubic equations. Al-Khayyam solved all attainable situations of such equations through the use of geometrical techniques, occasionally concerning conic sections akin to parabolas and hyperbolas. The proofs offered are exact and extremely deep. the writer made due acknowledgment and referral to the paintings and contributions of others who got here prior to him. a contemporary reader might be astonished through the prime quality of the paintings, linguistically in addition to mathematically. Historians of technology, academics of arithmetic and mathematicians themselves will locate the e-book either attention-grabbing and informative.

**Read Online or Download An Essay by the Uniquely Wise 'Abel Fath Omar Bin Al-khayam on Algebra And Equations: Algebra Wa Al-Muqabala (Great Books of Islamic Civilization) PDF**

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**Additional info for An Essay by the Uniquely Wise 'Abel Fath Omar Bin Al-khayam on Algebra And Equations: Algebra Wa Al-Muqabala (Great Books of Islamic Civilization)**

**Example text**

All the sequential triplicates constitute fifteen types, and they can be solved using the properties of the circle. The triplicate ones in every four consecutive ranks constitute twenty-four types, and can be solved using conic sections. Further, all the quartiles among every four consecutive ranks constitute twenty-eight types, and can be solved using properties of conic sections. So all the types (which fall within these seven ranks that can be solved using our methods) amount to eighty-six; only six were mentioned in the books of ancient algebraists.

We make the parallelepiped whose base is the square of ab and height hb, common, so the cube bh plus this parallelepiped equals the (volume of the) cube whose base is ab and height is bc, which we assumed to equal the given number. c h b z d m But the parallelepiped whose base is the square of ab (which is the number of the roots) and whose height is bh, which is the side of the cube, equals the given number of the sides of the cube hb. Hence the cube hb plus the assumed number of its sides equals the given number, which is the desired result.

But the ratio of hm (which equals bt) to mb (which equals ht, which is a line of order of the other section) is equal to the ratio of ht to ab (which is the right side of the conic section). So the four lines are proportional. Hence the ratio of ab to mb is the same as the ratio of mb to bt, and is as the ratio of bt to cm. Now, the ratio of the square of ab (the first) to the square of mb (the second) is the same as the ratio of mb (the second) to cm (the fourth). Hence the cube of mb equals (the volume of) the parallelepiped whose base is the square of ab and height equals cm because their heights are equivalent to their bases.

### An Essay by the Uniquely Wise 'Abel Fath Omar Bin Al-khayam on Algebra And Equations: Algebra Wa Al-Muqabala (Great Books of Islamic Civilization) by Omar Al-khayam

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